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August 30, 2014

August 30, 2014

Posted by **Anonymous** on Thursday, July 12, 2012 at 11:34am.

Rewrite the expression as an algebraic expression in x. sin(2cos^-1x)

- math -
**Steve**, Thursday, July 12, 2012 at 11:51amsin(v+x) = sinv*cosx + cosv*sinx

sin(v-x) = sinv*cosx - cosv*sinx

subtract to get

2cosv*sinx

sin(cos^-1 x) = √(1-x^2)

by definition, cos(cos^-1 x) = x

sin(2cos^-1 x) = 2sin(cos^-1 x)cos(cos^-1 x)

= 2√(1-x^2) * x

= 2x√(1-x^2)

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