Post a New Question

Integrated Math 1

posted by .

Suppose a parabola has its vertex at (0, 1) and its zeros at x = -2 and x = 2. Then equals _____.
A. 1-1/4x^2
B. 4-x^2
C. X^2-1
D. X^2-4

  • Integrated Math 1 -

    The vertex is at (0,4) sorry, I copied it wrong.

  • Integrated Math 1 -

    since the vertex is above the x-axis, we will have (with a > 0)

    y = -a(x-h)^2 + k

    We know (h,k) = (0,4), so

    y = -ax^2 + 4

    Since y(2) = 0, 0=-4a+4, so a=1

    y = -x^2 + 4, so (B)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question