Posted by Tifini on Thursday, July 12, 2012 at 9:30am.
Suppose a parabola has its vertex at (0, 1) and its zeros at x = 2 and x = 2. Then equals _____.
A. 11/4x^2
B. 4x^2
C. X^21
D. X^24

Integrated Math 1  Tifini, Thursday, July 12, 2012 at 9:34am
The vertex is at (0,4) sorry, I copied it wrong.

Integrated Math 1  Steve, Thursday, July 12, 2012 at 10:08am
since the vertex is above the xaxis, we will have (with a > 0)
y = a(xh)^2 + k
We know (h,k) = (0,4), so
y = ax^2 + 4
Since y(2) = 0, 0=4a+4, so a=1
y = x^2 + 4, so (B)
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