The solutions to the quadratic equation x^2+3x-4=0 are?

(more then one answer)
A. -4
B. 1
C. -1
D. 0
E. 4
F. There are no real roots.

since x^2+3x-4 = (x+4)(x-1), what do you think?

Ohh! I get it now, thank you!

Ya gotta love those aha! moments.

To find the solutions to the quadratic equation x^2+3x-4=0, we need to use the quadratic formula. The quadratic formula states that for an equation in the form ax^2+bx+c=0, the solutions are given by:

x = (-b ± √(b^2-4ac)) / (2a)

In our equation, a = 1, b = 3, and c = -4. Substituting these values into the quadratic formula, we get:

x = (-3 ± √(3^2 - 4(1)(-4))) / (2(1))
x = (-3 ± √(9 + 16)) / (2)
x = (-3 ± √25) / 2
x = (-3 ± 5) / 2

Simplifying further, we have two possible solutions:

1. x = (-3 + 5) / 2 = 2 / 2 = 1
2. x = (-3 - 5) / 2 = -8 / 2 = -4

Therefore, the solutions to the given quadratic equation are:
A. -4
B. 1