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October 20, 2014

October 20, 2014

Posted by **Manda** on Wednesday, July 11, 2012 at 10:18pm.

a) Show that the triangle formed by XYZ is right-angled.

b) Show that the perpendicular bisectors of XZ and YZ intersect at the centre of the base.

- geometry -
**Steve**, Thursday, July 12, 2012 at 9:10amthe center of the circle is at O(6,10)

OX = 5

So, the equation of the circle with diameter XY and center O is (x-6)^2 + (y-10)^2 = 25

OZ = 5, so Z is on that circle. Any triangle with the circle's diameter as one side, and a point on the circle is a right triangle.

Since Z is on the circle, XZ and YZ are two chords; their perpendicular bisectors intersect at O.

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