Posted by Manda on Wednesday, July 11, 2012 at 10:18pm.
the center of the circle is at O(6,10)
OX = 5
So, the equation of the circle with diameter XY and center O is (x-6)^2 + (y-10)^2 = 25
OZ = 5, so Z is on that circle. Any triangle with the circle's diameter as one side, and a point on the circle is a right triangle.
Since Z is on the circle, XZ and YZ are two chords; their perpendicular bisectors intersect at O.
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