Posted by Edward on Wednesday, July 11, 2012 at 12:18pm.
how many RPM are required to attain 1g with a radius of 840 feet

physics  MathMate, Wednesday, July 11, 2012 at 6:59pm
acceleration, a = rω² ft/s²
g=32.2 ft/s²
1 RPM = 2π rad/60 s
=π/30 rad/s
Let x=RPM required, then
ω=πx/30 rad/s
You need
g=rω²=r(πx/30)²
Solve for x.