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September 19, 2014

September 19, 2014

Posted by **Elizabeth** on Wednesday, July 11, 2012 at 12:01pm.

The answer is x=8/3 but I got x=7/2.

- Calculus -
**Steve**, Wednesday, July 11, 2012 at 12:27pmy = x√(4-x)

y' = 1√(4-x) + x * 1/2 * 1/√(4-x) * -1

= √(4-x) - x/(2√(4-x))

= (2(4-x) - x)/(2√(4-x))

= (8-3x)/(2√(4-x))

assuming x≠4, we just have to find where the numerator is zero.

x = 8/3

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