Posted by **delwin** on Wednesday, July 11, 2012 at 9:12am.

Find the radius of a circle on which a central angle of 3 pie over 2 radians subtends an arc of 60 ft.

- trigonometry -
**Jai**, Wednesday, July 11, 2012 at 10:07am
First note that a whole circle measures 360 degrees or 2pi radians. The 3/2pi radians is just 3/4 of 2pi, Thus we can say that the length of arc given (the 60 ft) is just 3/4 of the circumference of the circle.

If 60 is just 3/4 of the whole, then 60/(3/4) = 80 ft is the circumference of the circle.

Recall that the circumference of circle is given by

C = 2*pi*r

where r = radius

Substituting,

80 = 2*pi*r

r = 80/(2*pi)

r = 40/pi = 12.74 ft

hope this helps~ :)

- trigonometry -
**Bosnian**, Wednesday, July 11, 2012 at 10:11am
If a central angle theta = 3 pi / 2 then :

Circumference of a circle = 2 * r * pi

Ful circle have 360 ° = 2 pi radians.

Lenght of arc :

L = ( theta / 2 pi ) * 2 * r * pi

L = theta * r = 60

( 3 pi / 2 ) * r = 60 Multiply both sides by 2

3 pi * r = 120 Divide both sides by 3 pi

r = 120 / 3 pi = 40 / pi

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