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October 2, 2014

October 2, 2014

Posted by **Dave** on Tuesday, July 10, 2012 at 8:41pm.

-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.

- physics -
**bobpursley**, Tuesday, July 10, 2012 at 9:00pmhf=hi+vi*t+1/2 a t^2

0=1000-10t-4.9t^2

solve the quadratic

t=(-10+-sqrt(100+19600))/-9.8

t=-150/-9.8=15.3sec

check that.

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