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March 24, 2017

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sin t /1-cos t - 1+ cos t/sin t= 0

  • trig - ,

    sin t /(1-cos t) - (1+cos t)/sin t

    sin t (1+cos t)/((1-cos t)(1+cos t)) - (1+cos t)/sin t

    sin t (1+cos t)/(1-cos^2 t) - (1+cos t)/sin t

    sin t (1+cos t)/sin^2 t - sin t (1+cos t)/sin^2 t

    0

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