Posted by **Sammy** on Tuesday, July 10, 2012 at 4:05pm.

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.

2y=5x^(1/2) , y=4 and 2y+1x=6

I've been trying this problem for about 3 hours.

Please help!!!!!

- Calculus -
**Steve**, Tuesday, July 10, 2012 at 4:23pm
The region of interest is a triangle-ish area. The intersections are

(-2,4) (64/25,4) (1,5/2)

wrt x, divide region into two parts:

∫[-2,1] 4 - (6-x)/2 dx

+ ∫[1,64/25] 4 - 5/2 √x dx

= 9/4 + 27/25 = 333/100

wrt y,

∫[5/2,4] 4/25 y^2 - (6-2y) dy

= 333/100

- Calculus -
**Sammy**, Tuesday, July 10, 2012 at 4:31pm
Thank you so much!!!!!

- Calculus -
**Steve**, Tuesday, July 10, 2012 at 5:30pm
no sweat. Hang in there and after a few hundred more of these, they'll be a piece of cake!

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