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Find the center, foci, and vertices of this hyperbola 16x^2-y^2-32x+8y+16=0

  • math - ,

    16x^2 - 32x + 16 - y^2 + 8y - 16 = -16 + 16 + 16

    16(x-1)^2 - (y-4)^2 = 16

    (x-1)^2 - (y-4)^2/16 = 1

    h=1, k=4
    a=1, b=4, c=√17
    center: (1,4)
    foci: (1-√17,4) (1+√17,4)
    vertices: (0,4) (2,4)

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