Posted by **zzozo** on Tuesday, July 10, 2012 at 5:15am.

A small closed bottle is filled with water to adepth of 30 cm .A small hole located 10 cm above the bottom of the bottle is then opened .What is the speed of the water emerge from the hole in m\sex unit

- PHYICAL -
**Damon**, Tuesday, July 10, 2012 at 5:21am
(1/2) m v^2 = m g h

v = sqrt (2 g h) where h = 20 cm = .20 m

- PHYICAL -
**drwls**, Tuesday, July 10, 2012 at 6:52am
The speed of the water will be in m/s units, not m/sex

- PHYICAL -
**Elena**, Tuesday, July 10, 2012 at 10:00am
h=0.30 m, hₒ=0.10 m.

Bernoulli’s equation between the top surface and the exitting stream:

Pₒ+0+ρghₒ=Pₒ+ρv²/2+ ρgh,

v² = 2g(hₒ-h),

v=sqrt{2g(hₒ-h)}=sqrt{2•9.8•(0.30-0.10)} =...

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