Posted by James on Monday, July 9, 2012 at 4:28pm.
It depends if you are looking at a distribution of scores or a distribution of means.
Since the scores cannot vary more than 2 SD in either direction, I assume that you are looking for means.
90% = mean ± 2.04 SEm
SEm = SD/√n
95% = mean ± 1.96 SEm
99% = mean ± 2.575 SEm
I'll let you do the calculations.
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