Posted by **Tifini** on Monday, July 9, 2012 at 2:51pm.

Suppose a parabola has its vertex at (0, 1) and its zeros at x = -3 and x = 3. Then equals _____.

A. 9-x^2

B. 1-1/9x^2

C. x^2-1

D. x^2-9

- Integrated Math 1 -
**Steve**, Monday, July 9, 2012 at 4:57pm
vertex at (0,1) means y = -ax^2 + 1 where a>0.

since y=0 when x=3, we have

y = -1/9 x^2 + 1

(B)

- Integrated Math 1 -
**Henry**, Monday, July 9, 2012 at 4:57pm
B. Y = 1-(1/9)x^2 = 1 - x^2/9.

V(0,1).

When Xv = 0,

Y = 1-0/9 = 1.

When X = -3,

Y = 1 - (-3)^2 / 9 = 1--1 = o.

When X = 3,

Y = 1- 3^2 / 9 = 1 - 1 = 0.

Choice B satisfies all requirements.

Therefore,the answer is B.

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