5.82 g of CuNO3 is dissolved in water to make a 0.240 M solution. What is the volume of the solution?
mols CuNO3 = 5.82g/molar mass
Then M = mols/L soln
You know M and mols, solve for L.
Note: I assume you meant to type CuNO3.l
To find the volume of the solution, we need to use the formula:
Molarity (M) = Moles (n) / Volume (V)
First, let's find the number of moles of CuNO3:
Moles (n) = Mass (m) / Molar Mass (M)
The molar mass of CuNO3 can be calculated by summing up the atomic masses of its constituent elements:
Molar Mass (M) = (Atomic Mass of Cu) + (Atomic Mass of N) + (3 x Atomic Mass of O)
Atomic Mass of Cu = 63.55 g/mol
Atomic Mass of N = 14.01 g/mol
Atomic Mass of O = 16.00 g/mol
Molar Mass (M) = 63.55 + 14.01 + (3 x 16.00) = 125.56 g/mol
Now, we can calculate the number of moles:
Moles (n) = 5.82 g / 125.56 g/mol ≈ 0.0464 mol
Next, we rearrange the formula to solve for the volume:
Volume (V) = Moles (n) / Molarity (M)
Plugging in the values:
Volume (V) = 0.0464 mol / 0.240 mol/L ≈ 0.193 L
Therefore, the volume of the solution is approximately 0.193 liters.