algebra 2
posted by leo on .
SOLVE= log[6](x+3)+log[6](x+2)<2
A)6<x<7
B)6<x<2
C)3<x<7
D)2<x<3
PLEASE HELP!!

log[6](x+3)+log[6](x+2)<2
log[6]((x+3)(x+2))<2
(x+3)(x+2) < 36
x^2 + 5x + 6 < 36
x^2 + 5x  30 < 0
1/2 (5√145) < x < 1/2 (5+√145)
Hmm. There appears to be a typo. However,
(x3)(x+2) < 36
x^2  x  6 < 36
x^2  x  42 = 0
(x7)(x+6) < 0
6 < x < 7