the perimeter of the school is 128m. it is 24m wide. how long is it.what is it's area
P = 2L + 2W
128 = 2L + 2(24)
128 = 2L + 48
80 = 2L
40 = L
~~~~~~~~~~~~~~~~~~~~~~~~~~~
A = LW
suers!!
3072m²
3072m²
To find the length of the school, we can subtract the width from the perimeter. The perimeter is given as 128m, and the width is given as 24m.
Perimeter = 2 × (Length + Width)
Substituting the given values:
128m = 2 × (Length + 24m)
To solve for Length, we can rearrange the equation:
Length + 24m = 128m / 2
Length + 24m = 64m
Subtracting 24m from both sides:
Length = 64m - 24m
Length = 40m
So, the length of the school is 40m.
To find the area of the school, we can multiply the length by the width.
Area = Length × Width
Substituting the given values:
Area = 40m × 24m
Area = 960 square meters
Therefore, the area of the school is 960 square meters.