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Posted by jen on Sunday, July 8, 2012 at 4:28pm.

If 1.5% of the bolts made by an automotive factory are defective, what is the probability that in a shipment of 200 bolts, there are 6 defective bolts? Place your answer, rounded to four decimal places, in the blank.

prob (defective) = .015 prob(not defective) = .985 prob (6 of 200 defective) = C(200,6) (.015)^6 (.985)^194 = .0500

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