In the balanced equation for the combustion of CH3CH2OCH2OCH2OCH2CH3, the coefficient of the organic compound is...
the coefficient of oxygen gas is…
the coefficient of carbon dioxide gas is…
the coefficient of liquid water is…
hint: in case your view of the formula is partially obstructed, it is CH3CH2OCH2OCH2OCH2CH3
Do it the easy way. Collapse that unwieldy organic compounds to what matters. C H and O.
C6H14O3 + 8O2 ==> 6CO2 + 7H2O
To determine the coefficients in a balanced chemical equation, you need to understand the law of conservation of mass. This law states that atoms cannot be created or destroyed during a chemical reaction; they are merely rearranged.
Let's break down the combustion of CH3CH2OCH2OCH2OCH2CH3:
CH3CH2OCH2OCH2OCH2CH3 + O2 → CO2 + H2O
To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
In the organic compound (CH3CH2OCH2OCH2OCH2CH3), we have:
- 14 carbon atoms (C)
- 30 hydrogen atoms (H)
- 2 oxygen atoms (O)
On the product side, we need to have the same number of each atom. So, we have:
- Carbon dioxide (CO2): 1 carbon atom and 2 oxygen atoms
- Water (H2O): 2 hydrogen atoms and 1 oxygen atom
Now, we can determine the coefficients:
- The coefficient of the organic compound (CH3CH2OCH2OCH2OCH2CH3) is typically 1, so it doesn't appear explicitly in the balanced equation.
- The coefficient of oxygen gas (O2) is also determined by balancing the equation. In this case, since we have 2 oxygen atoms on the product side (CO2 and H2O), we need 5 oxygen molecules (O2) on the reactant side.
- The coefficient of carbon dioxide gas (CO2) is 1, as we have only 1 carbon atom on the reactant side.
- The coefficient of liquid water (H2O) is also 1, as we have 2 hydrogen atoms on the product side (H2O).
So, the balanced equation would look like this:
C6H14 + 9O2 → 6CO2 + 7H2O