Posted by **Jason** on Saturday, July 7, 2012 at 11:13pm.

You mix 19.5 gallons of a mixture containing 12 wt% NaCl (sol'n density = 1.0837 g/cm^3) with V2-gallon sol'n that is 20 wt% NaCl (sol'n density = 1.1453 g/cm^3). Needed mixture is 19 wt% NaCl

Whats the V2 in gallons?

(all solutions are in water so just dealing with NaCl)

- Chemistry -
**Gaurav**, Sunday, July 8, 2012 at 1:43am
V1 =19.5gellon=2113.2cm^3

TM1 =2113.2*1.0837= 22900.9 g

M1= 12*TM1= 2748.1 g

V2 =?

TM2 =V2*1.1453

M2 = 20*V2*1.1453

V3=V1+V2 (mixing of two solutions)

Conservation of mass:

M3=M1+M2,

M3= 12*V1*1.0837 + 20*V2*1.1453 ....I

TM3 = TM1+TM2,

M3 = 19*TM3

= 19*(V1*1.0837 + V2*1.1453) ......II

equate equation I and II

(you have value of V1, so its just 1 variable equation)

V2= 129.158 gellons Ans

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