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Use the 2nd derivative test to find the extremer of f on the interval [0,2PI]
f(x)=2cosx+sin 2x

  • calculus - ,

    Ack, I forgot, I don't seem to have a problem with numbers but when it comes to the sin and cos...I am not sure how to derive them. I want to say that 2cosx would end up being something like 2-sinx (x)...but then I feel like there's something wrong w/that scenario.

  • calculus - ,

    first derivative:
    -2sinx + 2cos 2x
    2nd derivative:

    -2cosx - 4sin 2x

    take it from there

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