Homework Help: physics

Posted by Natasha on Friday, July 6, 2012 at 3:03pm.

Two resistors, 68.0 Ω and 74.0 Ω, are connected in parallel. The current through the second resistor is 4.60 A.
(a) Determine the current in the first resistor?
(b) What is the total power supplied to the two resistors?

physics - Elena, Friday, July 6, 2012 at 3:27pm
U=I1•R1=I2•R2,
I1=I2•R2/R1=
=4.6•74/68 = 5.01 A.
1/R=1/R1+1/R2,
R=R1•R2/(R1+R2) = 68•74/(68+74)=35.44 Ohm.
I=I1+I2=4.6+5.01=9.61 A.
P=I²•R=(9.61)² •35.44 = 3273 Watt.

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