Posted by **kenny** on Friday, July 6, 2012 at 12:21pm.

Solve by setting up the proper equation to describe the facts given and then carrying out the mathematical calculations to solve for the unknown variable(s).

Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.

Show answer in the following format #,#,#.

- math -
**bobpursley**, Friday, July 6, 2012 at 12:29pm
Va+Vb+Vc=54

The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. This statement is not definitive.

does it mean Va=2Vb AND Va=1/3 Vc or does it mean

Va=2Va+1/3 Vc OR does it mean

Va=2(Va+1/3 Vc).

The problem cannot be solved until that is known.

- math -
**David**, Friday, July 6, 2012 at 1:10pm
nonsense. let the three batteries by A,B,C

then A = 2B

3A = C

A + B + C = 54

so A = 12

B = 6

C = 36

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