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April 16, 2014

April 16, 2014

Posted by **kenny** on Friday, July 6, 2012 at 12:21pm.

Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.

Show answer in the following format #,#,#.

- math -
**bobpursley**, Friday, July 6, 2012 at 12:29pmVa+Vb+Vc=54

The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. This statement is not definitive.

does it mean Va=2Vb AND Va=1/3 Vc or does it mean

Va=2Va+1/3 Vc OR does it mean

Va=2(Va+1/3 Vc).

The problem cannot be solved until that is known.

- math -
**David**, Friday, July 6, 2012 at 1:10pmnonsense. let the three batteries by A,B,C

then A = 2B

3A = C

A + B + C = 54

so A = 12

B = 6

C = 36

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