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November 27, 2014

November 27, 2014

Posted by **Parker** on Friday, July 6, 2012 at 9:46am.

I can substitute u=arctan x to get:

Integrate (sec u)^3 du over [0,arctan(2*pi)]

From there, I'm stuck.

(thanks Count Iblis for your last help)

- calculus -
**Parker**, Friday, July 6, 2012 at 10:17amnevermind, I got it. The trick was using trigonometric reduction formulas.

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