Posted by **Parker** on Friday, July 6, 2012 at 9:46am.

Integrate sqrt(x^2 + 1) dx over [0,2*pi]

I can substitute u=arctan x to get:

Integrate (sec u)^3 du over [0,arctan(2*pi)]

From there, I'm stuck.

(thanks Count Iblis for your last help)

## Answer This Question

## Related Questions

- Calculus - Calc length of arc of y=ln(x) from x=1 to x=2 ---- So far: Definite ...
- calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...
- Calculus - integrate t*(t^2 - 1)^(1/3) dt over (0,3) I substitute u = t^2 - 1 ...
- Integral calculus - Please do help solve the followings 1) Integrate e^4 dx 2) ...
- precal - The values of x that are solutions to the equation cos^(2)x=sin2x in ...
- Math/Calculus - Integrate: (2x^2+5)/((x^2+1)(x^2+4)) I came up with: (tan^-1)(x...
- calculus - Integrate: dx/sqrt(x^2-9) Answer: ln(x + sqrt(x^2 - 9)) + C I'm ...
- PRE-CALC - sin(arctan(-4/3) okay so i made arctan(-4/3) = x so im solving for ...
- Calculus - 1.Evaluate: (1/(x*sqrt(x^2-4)) I know the answer is -1/2*arctan(2/...
- Calculus - Note that pi lim arctan(x ) = ---- x -> +oo 2 Now evaluate / pi \ ...

More Related Questions