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Posted by on Friday, July 6, 2012 at 9:46am.

Integrate sqrt(x^2 + 1) dx over [0,2*pi]

I can substitute u=arctan x to get:

Integrate (sec u)^3 du over [0,arctan(2*pi)]

From there, I'm stuck.

(thanks Count Iblis for your last help)

  • calculus - , Friday, July 6, 2012 at 10:17am

    nevermind, I got it. The trick was using trigonometric reduction formulas.

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