Posted by **Maihul** on Friday, July 6, 2012 at 7:04am.

A bus starts frm rest and moves with a uniform acceleration of (1m/secondsquare) for 5 minutes. calculate the velocity and distance?? plz explain and also give me the correct answer

- physics -
**Anonymous**, Friday, July 6, 2012 at 9:10am
Bus starting from rest means Vi and Xi = 0

(where Vi is initial velocity and Xi is initial position).

5 mins = 300 seconds.

Vf = Vi + a*t (Vf is final velocity, a is acceleration, t is time).

Therefore,

Vf = 0 + 300*1 = 300 m/s.

For distance,

Xf = Xi + Vi*t + a*t^2*(0.5).

Xf = 0 + 0*t + (1)*(300)^2*0.5

Xf = 45000 m.

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