Posted by Maihul on Friday, July 6, 2012 at 7:02am.
The speed of the train is v = 36 km/h =36000/3600=10 m/s,
L is the length of the train,
S is the length of the bridge.
The time of passing the bridge begins when head end of the train enters the bridge and ends when its rear end leaves the bridge, therefore, the distance is s=L+S=200+400=600 m
t=s/v =600/10=60s
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