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April 19, 2014

April 19, 2014

Posted by **Maihul** on Friday, July 6, 2012 at 7:02am.

- physics -
**Elena**, Friday, July 6, 2012 at 2:38pmThe speed of the train is v = 36 km/h =36000/3600=10 m/s,

L is the length of the train,

S is the length of the bridge.

The time of passing the bridge begins when head end of the train enters the bridge and ends when its rear end leaves the bridge, therefore, the distance is s=L+S=200+400=600 m

t=s/v =600/10=60s

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