posted by Kellie on .
P H20 vapor= .0313atm
P air= .9687 atm
you increase the temperature to 338K; the total pressure remains 1 atm, but the volume increases. Determine the volume at the new temperature (assume water vapor reaches equilibrium at 338K)
PLEASE help!! i've been attempting this problem for hours with no luck :(
I'm a little confused about the problem Will you please repost (at this post) exactly as the problem is quoted to you. Also, if you have an answer post it too and I'll take a crack at it.