Posted by **Kellie** on Thursday, July 5, 2012 at 11:26pm.

Given:

Ti=298K

V=.005 L

Pt=1 atm

P H20 vapor= .0313atm

P air= .9687 atm

you increase the temperature to 338K; the total pressure remains 1 atm, but the volume increases. Determine the volume at the new temperature (assume water vapor reaches equilibrium at 338K)

PLEASE help!! i've been attempting this problem for hours with no luck :(

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