given the equation 2x-8y=8, determine as coordinates

(a)the x intercept (b) the y intercept
A (a)(0,0) B (a)(-4,0) C(a)(4,0)
(b)(0,1) (b)(0,-1) (b)(0,-1)

D (a)(-1,0)
(b)(0,4)
would it be a,b,c,d and how did you get it

2x - 8y = 8.

The x-int. is the value of x when Y = 0:
2x - 8*0 = 8
2x = 8
X = 4 = x-int.
(4,0).

The y-int. is the value of Y when x = 0:
2*0 - 8y = 8
-8y = 8
Y = -1 = y-int.
(0,-1).

To determine the x-intercept and y-intercept from the given equation, we need to substitute 0 for the variable that we want to find intercepts for and solve for the other variable.

(a) The x-intercept occurs when y = 0. By substituting y=0 into the equation, we get:
2x - 8(0) = 8
2x = 8
Dividing both sides by 2, we find:
x = 4

So, the x-intercept is (4, 0).

(b) The y-intercept occurs when x = 0. By substituting x=0 into the equation, we get:
2(0) - 8y = 8
-8y = 8
Dividing both sides by -8, we find:
y = -1

So, the y-intercept is (0, -1).

Comparing the answers to the given options, we find that the correct answer is C(a) (4, 0) for the x-intercept and C(b) (0, -1) for the y-intercept.