a company was charged $290 for 13 frames. it was charged $430 for 20 frames.

A. use the coordinates (13,290) and (20,430) to write a linear equation in point slope form that gives the relationship of the cost to the number of frames
B. find the cost for 25 frames.

You have posted 5 questions that are done the same way. I will do this one, and you do the previous 4

slope between the two points (13,290) and (20,430)
= (430-290)/(20-13) = 140/7 = 20

equation:
y-290 = 20(x-13)

arrange it in any way you want.
e.g.
y = 20x - 260 + 290
y = 20x + 30 would be the slope-yintercept form

What is the answer for B

To write a linear equation in point-slope form, we can use the formula:

y - y1 = m(x - x1)

where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.

Given the coordinates (13, 290) and (20, 430), we can find the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Using the coordinates (13, 290) and (20, 430), we have:

m = (430 - 290) / (20 - 13)
m = 140 / 7
m = 20

So, the slope (m) of the line is 20.

Now, let's choose one of the points to substitute into the point-slope form equation. Let's use (13, 290).

Using the formula, we have:

y - 290 = 20(x - 13)

Simplifying, we get:

y - 290 = 20x - 260

Adding 290 to both sides:

y = 20x - 260 + 290

y = 20x + 30

Therefore, the linear equation in point-slope form that represents the relationship between the cost and the number of frames is y = 20x + 30.

To find the cost for 25 frames, we can substitute x = 25 into the equation and solve for y.

y = 20x + 30
y = 20(25) + 30
y = 500 + 30
y = 530

So, the cost for 25 frames would be $530.