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September 30, 2014

September 30, 2014

Posted by **Lisa** on Thursday, July 5, 2012 at 7:56pm.

- algebra -
**Henry**, Monday, July 9, 2012 at 3:48pm1. Factor: x^2 - 2x - 3.

C = -3 = 1*(-3) = -1*3.

Select the pair whose algebraic sum = -2(1,and-3).

(x+1)(x-3).

The above method works best when the coefficient of x^2 is 1.

2. Factor: 2x^2 + x - 6.

The AC method should be used when the

coefficient of x^2 is not 1:

A*C=2*(-6) = -12 = -1*12 = -2*6 = -3*4.

Use the pair of factors whose algebraic

sum = B(1):

2x^2 + (-3x+4x) - 6.

Arrange the 4 terms to form 2

factorable binomials:

(2x^2+4x) + (-3x-6)

Factor each binomial:

2x(x+2) + -3(x+2)

(x+2)(2x-3).

These 2 methods take all of the guess work out of factoring.

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