Posted by andrew on Thursday, July 5, 2012 at 2:58pm.
a. Vf^2 = Vi^2 + 2*a*d
solve for Vi given Vf = 0 (speed at max height is 0), a = -9.81 m/s^2 and d = 3m.
b. Once you know Vi, you can use
Vf = a*t + Vi and solve for t.
(once again, Vf = 0 since you're only considering the path of the ball from the top of the building to maximum height)
c. Vf^2 = Vi^2 + 2*a*d
(d = height of building + 3m)
d. Vf = a*t + Vi
Use your answer from part c. to solve for the time it takes the ball to fall from max height to the ground and then add your answer from part b. to get the total time.
e,f,g: momentum = m*v
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