Post a New Question
posted by ted on Thursday, July 5, 2012 at 2:47pm.
How to fully factor X^3-8. pls help
The difference of cubes formula is: x^3 − y^3 = (x − y)*(x^2 + xy + y^2) Your x is x in this case and y = 8 (2^3). So you get: x^3 - 2^3 = (x - 2)*(x^2 + 2x + 4).
More Related Questions