Please help. Thanks.
1. Volt meter measures the potential between two large parallel plates to be 60 volts. The plates are 3cm apart. Find the magnitude of the electric field between them.
2. What work is done when 5C is raised potential by 12.45 volts?
* I really don't have any idea how to answer this please help. I need it asap cuz I have a test about this tomorrow at 7 am. And its now 8pm here in Philippines. :)
Don't worry, I'm here to help. Let's break down each question and find the answers step by step.
1. To find the magnitude of the electric field between two large parallel plates, you can use the formula:
Electric field (E) = Potential difference (V) / Distance between plates (d)
In this case, the potential difference is given as 60 volts and the distance between the plates is 3 cm. However, it's important to note that the electric field between two parallel plates is constant, assuming they are infinite in size. So, the magnitude of the electric field is the same throughout the space between the plates.
So, to find the electric field magnitude, plug in the given values into the formula:
E = 60 volts / 0.03 meters (converting 3 cm to meters)
E = 2000 volts/meter or 2,000 N/C (since 1 V/m = 1 N/C)
Therefore, the magnitude of the electric field between the parallel plates is 2000 N/C.
2. To find the work done when a charge is raised in potential, you can use the formula:
Work (W) = Charge (Q) x Potential difference (V)
In this case, the charge is given as 5 C and the potential difference is given as 12.45 volts.
Plug in the given values into the formula:
W = 5 C x 12.45 volts
W = 62.25 Joules (1 volt = 1 Joule/Coulomb)
Therefore, the work done when 5 C is raised in potential by 12.45 volts is 62.25 Joules.
I hope this helps! Let me know if you have any further questions. Good luck with your test!