Posted by **Hanna** on Wednesday, July 4, 2012 at 6:24pm.

at a throwing speed pf 12.2 meters per seconds,what is the angle that produce a distance of 13 meters

- Algebra & Trig -
**bobpursley**, Wednesday, July 4, 2012 at 7:45pm
under the influence of gravity?

consider the maximum height, velocity vertical is zero.

Vf=vi+gt

0=12sinTheta-9.8t

t=12sinTheta/9.8

time in the air is twice that time.

no, horizontal distance

13=12cosTheta*t=12cosTheta*2*12sinTheta/9.8

13=12^2/9.8 *2 cosTheta*sinTheta

remember siin2Theta=2sinTheta*cosTheta

solve for theta

13*9.8/144=sin 2Theta

check this.

Theta=50.6 deg

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