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Algebra & Trig

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at a throwing speed pf 12.2 meters per seconds,what is the angle that produce a distance of 13 meters

  • Algebra & Trig - ,

    under the influence of gravity?

    consider the maximum height, velocity vertical is zero.

    Vf=vi+gt
    0=12sinTheta-9.8t
    t=12sinTheta/9.8

    time in the air is twice that time.

    no, horizontal distance
    13=12cosTheta*t=12cosTheta*2*12sinTheta/9.8

    13=12^2/9.8 *2 cosTheta*sinTheta
    remember siin2Theta=2sinTheta*cosTheta

    solve for theta
    13*9.8/144=sin 2Theta
    check this.
    Theta=50.6 deg

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