Posted by Natasha on Wednesday, July 4, 2012 at 12:00am.
more info needed
here are the other charges
q1= +1.5e-9
q2=+4.0e10-9
Electric potential is a scalar, so you add the potential from each of the other charges.
Vtotal=v1+V2=k(q1/distance+q2/distance2)
Now, for the PE, EPE=Vtotal*q3
but i need two ansers for the epe of charge 3 at point a and b. do I just multiply the vtotal by q3 then multiply each charge by that to get the numer for pt a and b
diagonal of the square = 0.25•sqrt2=0.35 m.
point A (top, right)
φ1=k•q1/0.35 =9•10^9•1.5•10^-9/0.35 =38.6 V
φ2=k•q2/0.25 =9•10^9•4•10^-9/0.25 =144 V
φ = φ1+ φ2 = 182.6 V.
PE=q• φ =-4.35•10^-8• 182.6 = -7.94•10^-6 J.
point B (top, left)
φ1=k•q1/0.25 =9•10^9•1.5•10^-9/0.25 =54 V
φ2=k•q2/0.35 =9•10^9•4•10^-9/0.35 =102.9 V
φ = φ1+ φ2 = 156.9 V.
PE=q• φ =-4.35•10^-8• 156.9 = -6.82•10^-6 J.
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