A man (80kg) jumps from a 17 storey balcony (51 metres). How long would it take for him reach the ground?

~Sorry for the morbid example, we were just having a chat about it lol

h+g*t^2/2

t=sqrt(2h/g)
=sqrt(2*51/9.8)
= 3.2 sec

Assuming air resistance is negligible.

To calculate the time it takes for a person to reach the ground after jumping from a certain height, we can use the equation of motion known as the free fall equation.

The free fall equation is given by:

d = (1/2) * g * t^2

Where:
- d is the distance fallen (in meters)
- g is the acceleration due to gravity (which is approximately 9.8 m/s^2)
- t is the time taken (in seconds)

In this case, the distance fallen (d) is 51 meters, as the man jumps from a 17-story balcony (assuming each story is approximately 3 meters).

Plugging in the values into the equation, we get:

51 = (1/2) * 9.8 * t^2

Simplifying the equation:

51 = 4.9 * t^2

Dividing both sides of the equation by 4.9:

t^2 = 51 / 4.9

t^2 ≈ 10.41

To find the value of t (time), we take the square root of both sides:

t ≈ √10.41

t ≈ 3.2 seconds

Therefore, it would take approximately 3.2 seconds for the man to reach the ground after jumping from the 17-storey balcony.