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July 23, 2014

July 23, 2014

Posted by **Jezrell** on Tuesday, July 3, 2012 at 5:38pm.

Two electrons are 10^-15 meters apart. One electron is fixed on its position. The other, originally at rest, is released. How fast is the free electron moving when it is 10^-3 in from the fixed charge. (Solve using the Law of Conservation of Energy)

- physics -
**bobpursley**, Tuesday, July 3, 2012 at 5:55pmAssume the fixed electron is at zero PE, zero KE.

Then the PE of the original electron is -ke^2/1E-15

at the new position, energy is conserved, so new PE+KE=original PE

-ke^2/1E-15=-ke^2/1E-3 + KE

find KE, then KE= 1/2 m v^2

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