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January 31, 2015

January 31, 2015

Posted by **Isabella** on Tuesday, July 3, 2012 at 4:11pm.

- Calculus.. -
**Steve**, Tuesday, July 3, 2012 at 4:30pmx = 3-2sinθ

y = 1+5cosθ

since sin^2θ+cos^2θ = 1,

[(x-3)/2]^2 + [(y-1)/5]^2 = 1

(x-3)^2/4 + (y-1)^2/25 = 1

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