A loaded truck is going at a speed of 36 km/hr and a car starts at point 3 km behind the truck with an acceleration of 2 m/s. when will the car overtake the car? What is the distance covered by the car before it overtakes the car?

v1 =36 km/h =36000/3600=10 m/s
at²/2 - v1•t =sₒ
2 •t²/2- 10t=3000,
t² -10t-3000=0
t =10±sqrt(100+3000)= 10±55.68.
t=65.68 s.
s= at²/2=2•65.68²/2=4313.6 m.