Posted by **chan** on Tuesday, July 3, 2012 at 8:33am.

A loaded truck is going at a speed of 36 km/hr and a car starts at point 3 km behind the truck with an acceleration of 2 m/s. when will the car overtake the car? What is the distance covered by the car before it overtakes the car?

- physics -
**Elena**, Wednesday, July 4, 2012 at 5:03pm
acceleration has to be 2 m/s²(!!!)

v1 =36 km/h =36000/3600=10 m/s

at²/2 - v1•t =sₒ

2 •t²/2- 10t=3000,

t² -10t-3000=0

t =10±sqrt(100+3000)= 10±55.68.

t=65.68 s.

s= at²/2=2•65.68²/2=4313.6 m.

- physics -
**chan**, Thursday, July 5, 2012 at 12:13am
thanx it really ate my head

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