Post a New Question

chemistry 1046

posted by on .

Calculate the solubility (in grams per 1.00 102 mL of solution) of magnesium hydroxide in a solution buffered at pH = 9

the ksp of Mg(oh)2 = 2.06e-13

  • chemistry 1046 - ,

    ........Mg(OH)2 ==> Mg^2+ + 2OH^-
    E........x...........x.......2x

    Ksp = 2.06E-13 = (Mg^2+)(OH^-)
    For (Mg^+) substitute x
    For (OH^-)^2 substitute (2x + 1E-5)^2 [note: 2x for the Mg(OH)2 and 1E-5 for the OH^- concn of a soln with pH = 9
    Solve for x = solubility in mols/L, then correct that to mols/100 mL, then to g/100 mL.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question