Posted by Adam on Monday, July 2, 2012 at 11:28pm.
A)
The elastic potential energy stored in the spring would convert into KE of the box. This KE would be dissipated while working against the frictional force.
So work done = (1/2)Kx^2
= 800*0.5^2/2
= 100 Joules
B)
Frictional force F= mu*mg
F = 0.4*4*10 = 16 N
Work done = F*d
d = 100/16 = 6.25 m
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