A person who is properly constrained by an over-the shoulder seat belt has a good chance of surviving a car collision if the deceleration does not exceed about 30 "g"s (1.0 g= 9.8m/s^2)
Assumind uniform deceleration of this calue calculate the distance over which the front end of the car must be designed to collapse if a crash brings the car to rest from 60 km/h.
U^2 = 2*a*s
s = U^2/2*a = (16.66)^2/(2*30*9.8)
= 0.47m or 47 cm
To calculate the distance over which the front end of the car must be designed to collapse, we can use the equation:
d = (v^2) / (2a)
where:
- d is the distance
- v is the initial velocity
- a is the acceleration (deceleration in this case)
Given:
- The initial velocity (v) is 60 km/h
- To convert km/h to m/s, we need to divide it by 3.6, so the initial velocity (v) becomes 60 km/h * (1/3.6) = 16.67 m/s
- The deceleration (a) is 30 g (30 x 9.8 m/s^2)
Plugging the values into the equation, we get:
d = (16.67^2) / (2 * 30 * 9.8)
Calculating this equation will give us the distance (d) over which the front end of the car must be designed to collapse.