Posted by **Merc** on Monday, July 2, 2012 at 3:54pm.

Solve for x:

3sin^2(x)=cos^2(x) ; 0≤x≤2π

- math -
**Reiny**, Monday, July 2, 2012 at 4:00pm
3sin^2 x - cos^2 x = 0

3sin^2x - (1- sin^2 x) = 0

4sin^2 x = 1

sin^2 x = 1/4

sinx = ± 1/2

So x could in in all 4 quadrants,

(30°, 150°, 210°, and 330°)

x =π/6, 5π/6, 7π/6. and 11π/6

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