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posted by Lauren on Monday, July 2, 2012 at 12:52pm.
What is the minimum work in joules needed to push a 1460 kg car 14.0 m up a 12.5 degree incline? (Ignore friction.)
Work required = Gain in PE = m*g*h = 1460*9.8*14Sin12.5 J (h-vertical height gained)
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