To collect funds, the organization is holding a football match between teachers and students. Each ticket costs 2x+3y for students and 3x - 5y for non-students. What is the total earning if 2x - 3y students and 3x + 5y non-students would attend?
Replace the given algebraic expressions with actual numbers, figure out what you would do, then
repeat the same operations using the above algebraic expressions.
e.g. tickets cost $5 for students and $8 for teachers, there are 65 students and 4 teachers.
earnings = ??
To calculate the total earnings, we need to multiply the number of tickets sold by the price of each ticket.
First, let's find the price of each ticket for students and non-students:
- For students, each ticket costs 2x + 3y.
- For non-students, each ticket costs 3x - 5y.
To find the total earnings from the students, multiply the number of student tickets sold (2x - 3y) by the price of each student ticket (2x + 3y).
Total earnings from students = (2x - 3y) * (2x + 3y)
To find the total earnings from the non-students, multiply the number of non-student tickets sold (3x + 5y) by the price of each non-student ticket (3x - 5y).
Total earnings from non-students = (3x + 5y) * (3x - 5y)
To find the total earnings from both students and non-students, add the total earnings from students and the total earnings from non-students:
Total earnings = Total earnings from students + Total earnings from non-students
Therefore, the equation for total earnings is:
Total earnings = (2x - 3y) * (2x + 3y) + (3x + 5y) * (3x - 5y)