Posted by hi on Sunday, July 1, 2012 at 9:59pm.
Hey I am working on differentiation/quotient rule for this problem...can someone help me?
x^23/x2.

calculus  Steve, Monday, July 2, 2012 at 12:16am
if y=u/v,
y' = (u'vuv')/v^2
so, let u = x^23, u'=2x
let v = x2, v'=1
y' = ((2x)(x2)(x^23)(1))/(x2)^2
= (2x^22xx^2+3)/(x2)^2
= (x^24x+3)/(x2)^2
= (x3)(x1)/(x2)^2
or, you can always think of it as a product rule:
y = (x^23) * (x2)^1
y' = (2x3)/(x2)  (x^23)*(x2)^2
which works out the same
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