Friday

October 24, 2014

October 24, 2014

Posted by **hi** on Sunday, July 1, 2012 at 9:59pm.

x^2-3/x-2.

- calculus -
**Steve**, Monday, July 2, 2012 at 12:16amif y=u/v,

y' = (u'v-uv')/v^2

so, let u = x^2-3, u'=2x

let v = x-2, v'=1

y' = ((2x)(x-2)-(x^2-3)(1))/(x-2)^2

= (2x^2-2x-x^2+3)/(x-2)^2

= (x^2-4x+3)/(x-2)^2

= (x-3)(x-1)/(x-2)^2

or, you can always think of it as a product rule:

y = (x^2-3) * (x-2)^-1

y' = (2x-3)/(x-2) - (x^2-3)*(x-2)^-2

which works out the same

**Answer this Question**

**Related Questions**

Math - Calculus Question. - hey can someone explain to me the relationship ...

calculus - Alright so implicit differentiation is just not working out for me. ...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

Calculus - f(x)=5+(6/x)+(7/x^2), find f'(x). I haven't done fractions without ...

Calculus - Let f(x)= 5x ------- x–2 are we supposed to use the quotient rule? ...

Implicit Differentiation - Use implicit differentiation to find the slope of the...

Calculus - How do you use imlicit differentiation to differentiate e^(xy)? I ...

Calculus - I need to find the derivative of the following problem via ...

calculus help - Is there any good calculus websites out there that teach every ...

Calculus - Use the quotient rule to find f'(x): f(x) = [(x+4)(x-5)]/[2x(x+3)] ...