how many grams of NaOH are needed to react with two moles of H2SO4
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
1 mol H2SO4 needs 2 mols NaOH; therefore, 2 mol H2SO4 will need 4 mols NaOH. Then grams = mols x molar mass
so grams = 4 * 39.98 ? = 159.92
Ignoring significant figures, yes.
To find out how many grams of NaOH are needed to react with two moles of H2SO4, we need to first determine the balanced chemical equation for the reaction between NaOH and H2SO4.
The balanced chemical equation for the reaction is:
2 NaOH + H2SO4 -> Na2SO4 + 2 H2O
From the balanced equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4.
Given that we have 2 moles of H2SO4, we can use the molar ratio from the balanced equation to determine the amount of NaOH needed.
1 mole of H2SO4 requires 2 moles of NaOH.
Since we have 2 moles of H2SO4, we can multiply this by the molar ratio to find the moles of NaOH needed:
2 moles H2SO4 * (2 moles NaOH / 1 mole H2SO4) = 4 moles NaOH
Next, we can calculate the grams of NaOH needed using its molar mass.
The molar mass of NaOH is 22.99 g/mol (sodium) + 16.00 g/mol (oxygen) + 1.01 g/mol (hydrogen) = 39.00 g/mol.
To find the grams of NaOH needed, we multiply the moles of NaOH by its molar mass:
4 moles NaOH * 39.00 g/mol = 156 grams NaOH
Therefore, you would need 156 grams of NaOH to react with two moles of H2SO4.