Posted by **jo145578** on Sunday, July 1, 2012 at 5:11am.

a person walks up a stationary escalator in t1 second if he remains stationary on the escalator then it can take him up in t2 second if the length of the escalator is L,then

1.determine the speed of man with respect to escalator

2.determine the speed of escalator

3. how much time would it take him to walk up the moving escalator?

- science -
**ajayb**, Sunday, July 1, 2012 at 5:31am
1) Speed of man w.r.t.escalator = L/t1

2) Speed of escalator w.r.t.ground = L/t2

3)Speed of man w.r.t.ground = (L/t1)+(L/t2)

Time taken by man to cover distance(L) = L/(L/t1)+(L/t2)

= t1*t2/(t1+t2)

- mechanics -
**jose**, Tuesday, November 25, 2014 at 10:00am
if a man moves up the escalator and the escalator moves down he has, for example, Vm/g=2stair/s and the escalator has Ve/g =1stair/s, so we have resultant velocity =3stairs/s. Now, assume that as the escalator is not moving manīs Vm/g moving up is 20stairs/s. So the manīs velocity is Vm/g / 3 =20/2--> Vm/g =30stairs/s. Therefore his displacement is 30 stairs up

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