Monday

December 22, 2014

December 22, 2014

Posted by **Liz** on Saturday, June 30, 2012 at 2:17pm.

Funtion:

f(x)=1/sqrt(x-1)

Line:

x+2y+7=0

- Calculus -
**bobpursley**, Saturday, June 30, 2012 at 5:05pmf'=-1/2 * (x-1)^-1.5

that is the slope then tangent to the line.

y=-x/2-3.5

so slope is -1/2

f'=-1/2 * (x-1)^-3/2=-1/2

solving, x=2

then

y=1/sqrt(x-1)=1 so the point of tangency is 2,1

y=mx+b

2=-1/2 (1)+b

b=2.5

y=-x/2+2.5

check all this.

**Answer this Question**

**Related Questions**

calculus - 5. Let f be the function given by f(x) = x3- 7x + 6. a. Find the ...

calculus - Find an equation of the line that is tangent to the graph f and ...

Calculus-math - Find an equation of the line that is tangent tothe graph of f ...

Math- Calculus - Find an equation of the line that is tangent to the graph of f ...

MATH - Find an equation of the line that is tangent to the graph of f and ...

Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...

Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...

Calculus - Given the function y=(x^2-5/x+3), answer the following questions. a) ...

Math please help - Find an equation of the line that is tangent to the graph of ...

Calculas - Find an equation of the line that is tangent to the graph of f and ...