Posted by Liz on Saturday, June 30, 2012 at 2:17pm.
f'=-1/2 * (x-1)^-1.5
that is the slope then tangent to the line.
y=-x/2-3.5
so slope is -1/2
f'=-1/2 * (x-1)^-3/2=-1/2
solving, x=2
then
y=1/sqrt(x-1)=1 so the point of tangency is 2,1
y=mx+b
2=-1/2 (1)+b
b=2.5
y=-x/2+2.5
check all this.
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