Posted by **bhavana** on Saturday, June 30, 2012 at 12:30pm.

if f'(x)=cos^2x and f(1)=0 then f(x)=

- math -
**Steve**, Sunday, July 1, 2012 at 6:25am
cos^2x = (1+cos2x)/2

f(x) = x/2 + sin2x/4 + C

at x=1,

0 = 1/2 + 0 + C

C = -1/2

f(x) = x/2 + sin2x/4 - 1/2

= 1/4 (2x + sin2x - 2)

- math -- oops -
**Steve**, Sunday, July 1, 2012 at 6:28am
0 = 1/2 + sin(2)/4 + C

C = -1/4 (2 + sin2)

adjust final answer accordingly

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