math
posted by
bhavana on
.
if f'(x)=cos^2x and f(1)=0 then f(x)=

math 
Steve,
cos^2x = (1+cos2x)/2
f(x) = x/2 + sin2x/4 + C
at x=1,
0 = 1/2 + 0 + C
C = 1/2
f(x) = x/2 + sin2x/4  1/2
= 1/4 (2x + sin2x  2)

math  oops 
Steve,
0 = 1/2 + sin(2)/4 + C
C = 1/4 (2 + sin2)
adjust final answer accordingly